Regarding deflate-gate Amounton's Law says "The pressure of a gas of fixed mass and fixed volume is directly proportional to the gas's absolute temperature." So P/T = Constant For comparing the same substance under two different sets of conditions, the law can be written as: P 1 /T 1 = P 2 /T 2 I'm also going to do this in metric to avoid other potential errors. And I apologize that I am 30 years from doing this sort of work 12.5 psi = 86.18 kPa ( kiloPascals) 75F=23.89C = 297.04K 30F=-1.11C = 272.04K So 86.18/297.04 = P 2 /272.04 0.29= P 2 /272.04 P 2 =78.93kPa 78.93kPa= 11.45PSI Temperature change from 75F to 30F degrees would result in a football ball losing ~1 pound of pressure per square inch. Now this does not account for ALL of the claimed 2lbs PSI that was measued as having been lost -- but we don't know that the ball began at 12.5 -- what if they began at 12? What if they were inflated in a 78 degree room? I think ear...
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